(a) This is a combination reaction because two reactants form one product. The heat shows it is exothermic.
(b) This is a decomposition reaction because a single compound splits into simpler substances on heating.
(c) This is a displacement reaction because iron (more reactive) replaces copper from its compound.
(d) This is a double displacement reaction because ions exchange and form a precipitate (PbI₂).
Each reaction matches its pattern and observation.
Use the number of products/reactants, ion exchange, and reactivity to decide.
Q7. You must design a simple lab activity to prove displacement reactions using everyday metals. Plan the setup, predict results, and explain why they occur.
Answer:
Choose two metals: iron and copper. Prepare CuSO₄ solution in two test tubes.
Put a clean iron nail in tube A and a clean copper wire in tube B.
After 20–30 minutes, tube A: blue fades, copper deposits on iron, solution turns green (FeSO₄).
Tube B: no change because copper is less reactive and cannot displace iron.
This proves more reactive metal can displace a less reactive one.
It shows reactivity series in action and confirms displacement.
Keep safety: use gloves, avoid skin contact, and label tubes.
Q8. Two clear solutions are mixed and a sudden yellow solid appears while the liquid remains colorless. Identify the reaction type, propose possible reactants, and explain the ionic change.
Answer:
A sudden solid formation is a precipitation in a double displacement reaction.
Likely reactants: Pb(NO₃)₂(aq) and KI(aq).
They exchange ions: Pb²⁺ from lead nitrate meets I⁻ from KI.
PbI₂(s) forms as a yellow precipitate. K⁺ and NO₃⁻ stay in solution as spectator ions.
The key is ion exchange and low solubility of PbI₂.
Thus, the reaction is double displacement with precipitation.
Observations match the given example in the chapter.
Q9. A construction team is slaking quicklime (CaO) by adding water. Explain the reaction, the heat change, the safety steps, and why the process is useful.
Answer:
Quicklime (CaO) reacts with water to form slaked lime (Ca(OH)₂).
The reaction is CaO + H₂O → Ca(OH)₂ + heat. It is exothermic and gets very hot.
Safety: add water slowly, use gloves and goggles, and keep distance from the hot container.
The beaker warms because energy is released when new bonds form.
Slaked lime is used to make mortar and plaster in building work.
The reaction shows a combination type with clear heat release.
Proper control prevents splashing and burns.
Q10. In a school lab, you must confirm gases from decomposition reactions: CO₂ from CaCO₃ and SO₂ from FeSO₄. Plan simple tests and link them to the reaction type.
Answer:
For CaCO₃ → CaO + CO₂, pass gas through limewater (Ca(OH)₂); it turns milky due to CaCO₃.
For 2FeSO₄ → Fe₂O₃ + SO₂ + SO₃, the gas has a sharp smell; bring moist litmus: it turns red (acidic).
You can also note choking odor typical of SO₂/SO₃.
Both reactions are thermal decomposition because heat breaks the compounds.
Record color change (green to brown solid for FeSO₄ heating) and gas tests.
These observations confirm the products and the reaction type.
Always heat gently and use a fume hood or good ventilation.