Very Short Question and Answers - Equations of Motion

The speed acquired is 12 m/s.

The distance travelled is 720 m.

The train will go 810 m before coming to rest.

The velocity will be 60 cm/s.

The distance covered will be 200 m.

The height attained by the stone is 1.25 m.

Eq. (7.5) expresses the relationship v = u + at, relating final velocity to initial velocity, acceleration, and time.

Eq. (7.6) represents the position-time relation: s = ut + 1/2 at².

Eq. (7.7) relates position and velocity: 2as = v² - u².

The final velocity will be 20 m/s.

The distance covered will be 75 m.

The vehicle's initial speed was 12 m/s.

The object moves 24 m.

The uniform acceleration is 3 m/s².

The biker covers 150 m.

It will take 2 seconds to reach the highest point.

The total distance traveled is 20 m.

Uniform acceleration implies that the rate of change of velocity is constant over time.

No, the equations of motion are applicable only to objects moving with uniform acceleration.

The standard unit of acceleration is m/s².